63x+14=16x^2

Solution for 63x+14=16x^2 equation:

63x+14=16x^2

We move all terms to the left:

63x+14-(16x^2)=0

determiningTheFunctionDomain
-16x^2+63x+14=0

a = -16; b = 63; c = +14;
Δ = b2-4ac
Δ = 632-4·(-16)·14
Δ = 4865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{4865}}{2*-16}=\frac{-63-\sqrt{4865}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{4865}}{2*-16}=\frac{-63+\sqrt{4865}}{-32}
$